Using the Ideal Gas Law with V = 0.886 L, n = 0.00801 mol, T = 311 K, and R = 0.08206 L·atm/(mol·K), what is the pressure in atm?

• A. 2.31 atm
• B. 23.1 atm
• C. 0.002 atm
• D. 0.231 atm

Answer: (D)

This question uses the Ideal Gas Law, PV = nRT. Solve for pressure: P = nRT / V. With R in the units L·atm/(mol·K), the result will be in atmospheres when V is in liters and T in kelvin.

Compute nRT first: nRT = 0.00801 × 0.08206 × 311 ≈ 0.20442 atm·L. Then divide by the volume: P ≈ 0.20442 / 0.886 ≈ 0.231 atm.

So the pressure is about 0.231 atm.